if a playground is a rectangle that is enclosed by a exactly 140 ft of fence and the width is ten ft shorter then its length what is the width and length of the rectangle
Set up equations as follows:
Let the length be x,
the width is equal to length-10
=x-10
The perimeter, 140 ft
=2(x + (x-10))
or
2(x+(x-10))=140
Solve for x = length and calculate (x-10) = width.
the width is 30 and the lenghth is 40
To find the width and length of the rectangle, we can set up an equation based on the information given in the question.
Let's assume that the length of the rectangle is x ft. According to the question, the width is ten ft shorter than the length, so the width would be (x - 10) ft.
The perimeter of a rectangle can be found by adding up all four sides of the rectangle, which in this case is equal to 140 ft. So, we can write our equation as:
2(length + width) = 140
Plugging in the values we identified earlier:
2(x + (x - 10)) = 140
Simplifying the equation:
2(2x - 10) = 140
4x - 20 = 140
4x = 160
x = 40
Therefore, the length of the rectangle is 40 ft.
And since the width is 10 ft shorter than the length, the width would be (40 - 10) = 30 ft.
Thus, the width of the rectangle is 30 ft and the length is 40 ft.