Chemistry

What is the de Broglie wavelength of an oxygen molecule, O2 traveling at 521 m/s? Is the wavelength much smaller or much larger than the diameter of an atom. (on the order of 100 pm)

De Broglie wavelength = h/mv
h = Planck's constant in J*s.
m is mass in kg.
v is velocity in m/s

Okay for this one I did

6.63 X 10^-34 J*s/ (?kg) (6210 m/s)

I don't understand how I get the kg for the problem

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  1. sorry I copied the wrong problem it is supposed to be: 521 m/s not 6210 m/s
    6.63 X 10^-34/ (? kg)(521 m/s)

    How do I get the kg for this problem

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  2. 1 mol O2 has a mass of 32 g and contains 6.02 x 10^23 molecules OR 2 x 6.02 x 10^23 atoms. Therefore, 1 atom of oxygen has a mass of ???

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  3. 3.01 x 10^23 ???

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  4. Let's see now. Do you have any idea how large a number 3.01 x 10^23 grams is? Do you think 1 single atom of oxygen can weigh
    600,000,000,000,000,000,000,000 grams. That's one heavy atom.

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  5. yes I know how big that is but I figured that you had 2 atoms of 6.02 x 10^23 so I divided by 2 to get the mass of 1 mol which is 3.01 X 10^23...

    why wouldnt you just take the 100 pm and make it into kg.

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  6. Aha!. I wondered how you did it. But you KNOW 1 atom of oxygen can't possibly weigh that much. You can't even see 1 atom of oxygen so you know the mass of 1 atom must be very small. And your number isn't very small; it is very large. The mass of 1 mol is 32 grams. I told you that in my first response.
    1 mol (not 1 molecule) has a mass of 32 grams and contains 12.04 x 10^23 atoms of oxygen. So 1 atom must have a mass of
    (32 g/mol) x (1 mol/12.04 x 10^23 atoms) = ?? grams/1 atom.

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  7. so that equals 2.66 grams/ 1 atom

    now where do I go from there

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  8. Absolutely not!
    32/12.04 x 10^23 = WHAT. You dropped the exponent again.
    My calculator gives me 2.66 x 10^-23 grams.
    What next? Change this to kg, you have the other numbers, calculate lambda. That will come out in meters.

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  9. 2.66 X 10 ^-23 (0.001 kg/1 g) = 2.66X 10^-26

    that is what I want is kg

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  10. right

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  11. so I don't need to go any father I just plug this back into the original problem and get my answer right

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  12. right. You have h, mass, velocity. That's all you need to calculate lambda.

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  13. 6.63 X 10^-34/ (2.66X 10^-26 kg)(521 m/s) = 1.30 X 10^-5
    is this correct

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  14. No, but I gave you a bum steer. I re-read the problem and the problem states that it is an oxygen molecule, not an oxygen atom. Therefore, the masss of the oxygen MOLECULE (instead of atom) is
    32/6.02 x 10^23 = 5.32 x 10^-23 g or 5.32 x 10^-26 kg. Then
    lambda = 6.63 x 10^-34/(5.32 x 10^-26 x 521) = ??
    Check my work.

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