Please someone have mercy this is a test grade and I have no idea what to do !
A force of 200 N is being exerted on a blocki, which has a mass of 10 kg and is on 30 degrees inclined plane. The force is acting up the plane and parallel to it. The coefficient of friction between the block and the plane is .3 and the plane is 12 m long.
a. What is the weight of the block
b. What is the parallel force acting on the block down the incline?
c. What is the normal force acting on the block?
d. What is the frictional force acting on the block?
e. What is the net force acting on the block?
f. What is the acceleration of the block?
g. If the block starts in the middle of the plane, what is its speed at the end of the incline?
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Thank you Bob, but even after reading the article, I still don't understand how to obtain the parallel force acting on the block (question b). Can you expand perhaps?
Parallel force=mgsina
=(10kg)(9.8)(sin30)
=49N
9.8 is your gravitational constant
yyu
To solve this problem, you can apply Newton's second law of motion and use the given information about the force, mass, angle, coefficient of friction, and length of the inclined plane.
a. The weight of the block can be calculated using the formula:
Weight = mass × acceleration due to gravity
Given that the mass of the block is 10 kg and acceleration due to gravity is approximately 9.8 m/s², you can calculate the weight:
Weight = 10 kg × 9.8 m/s² = 98 N
b. The parallel force acting on the block down the incline can be determined by considering the force components along the inclined plane. The force acting parallel to the incline is equal to the applied force minus the force opposing it, which is the force of friction.
Parallel force = applied force - force of friction
In this case, the force of friction can be calculated using the formula:
Force of friction = coefficient of friction × normal force
c. The normal force acting on the block can be determined by considering the gravitational force acting on the block. The normal force is the force perpendicular to the inclined plane.
Since the block is on an incline, the normal force can be calculated using the formula:
Normal force = weight × cos(angle of incline)
d. Once you calculate the normal force, you can use it to determine the force of friction using the formula mentioned earlier.
Force of friction = coefficient of friction × normal force
e. The net force acting on the block can be determined by considering the force components along the inclined plane. The net force is the difference between the applied force and the force of friction.
Net force = applied force - force of friction
f. The acceleration of the block can be found using Newton's second law of motion:
Net force = mass × acceleration
Given the mass of the block (10 kg) and the net force calculated in the previous step, you can solve for the acceleration.
g. To determine the speed of the block at the end of the incline, you can use the kinematic equation:
Speed^2 = initial velocity^2 + 2 × acceleration × distance
Since the block starts with zero initial velocity, the equation simplifies to:
Speed^2 = 2 × acceleration × distance
Given the calculated acceleration and the length of the incline (12 m), you can solve for the speed at the end of the incline.