There are two similar triangles XYZ, and ABC. If x = 8, c = 5, and y = b, find z and a. How am I suppose to solve this problem if y = b? Do I find what b is first? Or will the answer be with a variable?
similar triangles have consecutive parts:
X=A;Y=B[given, this is a clue!];Z=C
So therefore if x=8, then a=8; if c=5, then z=5!!!
:)
Ohhh I get it! Thank you :D It took be 45seconds to figure that out, after you helped.
To solve this problem, we need to use the property of similar triangles, which states that corresponding sides of similar triangles are proportional.
Given that triangles XYZ and ABC are similar and y = b, we can write the following proportion based on the corresponding sides:
x / a = y / b = z / c
We are given that x = 8 and c = 5, so we can substitute these values into the proportion:
8 / a = y / b = z / 5
Now, since we know that y = b, we can replace y with b in our proportion:
8 / a = b / b = z / 5
Simplifying further, we have:
8 / a = 1 = z / 5
Now, we can solve for the missing variables. Since 8 divided by 1 is 8, we have:
8 / a = 1 => 8 = a
Similarly, since 1 multiplied by 5 is 5, we have:
1 = z / 5 => z = 5
Therefore, the solution to the problem is a = 8 and z = 5. So, a is the variable and z is a value.