Aluminum hydroxide and sulfuric acid neutralize to make water and aluminum sulfate.

the first step i have done:

Al(OH)3 + H2SO4 -> H2O + Al2(SO4)3

i find this one confusing XD

nevermind i got it

It's great that you've started working on balancing the chemical equation! Let's break it down step by step to make it less confusing.

The equation you provided is:

Al(OH)3 + H2SO4 -> H2O + Al2(SO4)3

To balance this equation, we need to make sure that there is an equal number of each type of atom on both sides. Let's start with the elements individually.

On the left side of the equation, we have one aluminum (Al), one sulfur (S), four oxygen (O), and six hydrogen (H) atoms. On the right side, we have three aluminum (Al) atoms, three sulfur (S) atoms, twelve oxygen (O) atoms, and two hydrogen (H) atoms.

To balance the number of aluminum atoms, we can add a coefficient of two in front of Al(OH)3 on the left side:

2 Al(OH)3 + H2SO4 -> H2O + Al2(SO4)3

Now, we have two aluminum atoms on both sides of the equation.

Next, let's balance sulfur. We already have three sulfur atoms on the right side, so we need three sulfur atoms on the left side as well. We can achieve this by adding a coefficient of three in front of H2SO4 on the left side:

2 Al(OH)3 + 3 H2SO4 -> H2O + Al2(SO4)3

Now, we have two aluminum atoms and six sulfur atoms on both sides of the equation.

Finally, let's balance hydrogen and oxygen. On the left side, we have twelve hydrogen atoms and eighteen oxygen atoms. On the right side, we have two hydrogen atoms and twelve oxygen atoms.

To balance hydrogen, we can add a coefficient of six in front of H2O on the right side:

2 Al(OH)3 + 3 H2SO4 -> 6 H2O + Al2(SO4)3

Now, we have twelve hydrogen atoms on both sides.

To balance oxygen, we need to add a coefficient of nine in front of Al2(SO4)3 on the right side:

2 Al(OH)3 + 3 H2SO4 -> 6 H2O + 2 Al2(SO4)3

Now, we have eighteen oxygen atoms on both sides.

So, the balanced equation is:

2 Al(OH)3 + 3 H2SO4 -> 6 H2O + 2 Al2(SO4)3

Remember, the coefficients in front of the compounds indicate the number of molecules or formula units, indicating the balanced equation.