Calculate the molecular mass of the nonionic solutes.
8.02 grams of solute in 861 grams of water lower the freezing point to
-0.430 celsius.
the freezing point of H2O is lowered 1.86 celsius per mole of solute.
the boiling point of H2O is raised 0.512 celsius per mole of solute.
What you have typed is interesting but you have no question.
you have to calculate the molecular mass of the nonionic solutes.
To calculate the molecular mass of the nonionic solute, we can use the formula:
ΔT = Kf * m
Where:
ΔT = Change in freezing point or boiling point (in degrees Celsius)
Kf = Cryoscopic constant or ebullioscopic constant (in degrees Celsius/mole)
m = Molality (moles of solute per kilogram of solvent)
In this case, we have the following information:
ΔT = -0.430°C (change in freezing point)
Kf = 1.86°C/mole (freezing point constant for water)
m = mass of solute / mass of solvent
Let's first calculate the molality (m):
mass of solvent = 861 grams of water = 0.861 kg
mass of solute = 8.02 grams
m = mass of solute / mass of solvent
m = 8.02 g / 0.861 kg
m = 9.32 mol/kg
Now, we can calculate the number of moles of solute:
ΔT = Kf * m
-0.430°C = 1.86°C/mole * 9.32 mol/kg
Now, rearranging the equation to solve for moles of solute:
moles of solute = ΔT / Kf
moles of solute = -0.430°C / 1.86°C/mole
moles of solute ≈ -0.231 mol
Since we are dealing with nonionic solutes, we know that the number of moles of solute is equal to the number of formula units. Therefore, the molecular mass of the nonionic solute is approximately equal to -0.231 grams.