1) A microphone has an area of 6.7 cm2. It receives during a 4.62 s time period a sound energy of 2.5x10-11 J. What is the intensity of the sound?
2) Using the intensity in the previous question, what is the variation of pressure in the sound wave if the speed of sound is 343 m/s and the density of air is 1.2 kg/m3?
How many times are you going to post this? I have answered it already. Look at your previous posts
science
To find the intensity of the sound in question 1, you can use the formula:
Intensity = Sound Energy / Time
Given that the microphone receives a sound energy of 2.5x10^-11 J during a 4.62 s time period, you can substitute these values into the formula:
Intensity = (2.5x10^-11 J) / (4.62 s)
Calculating this will give you the answer to question 1.
Now, moving on to question 2. To find the variation of pressure in the sound wave, you can use the formula:
Intensity = (Density * Speed of Sound * Pressure Amplitude^2) / 2
Plugging in the values for the intensity (calculated in question 1), speed of sound (343 m/s) and density of air (1.2 kg/m^3), you can solve for the pressure amplitude:
Intensity = (1.2 kg/m^3 * 343 m/s * Pressure Amplitude^2) / 2
Rearranging the formula and solving for the pressure amplitude will give you the answer to question 2.