Am I correct? Find the slope and the y intercept of y = - 10/3x - 9/2. The slope is -10/3 because this is what is in front of x and the y - intercept is (0, -9/2)?
The second question is I need to find the slope of a graph that was provided for me. The y intercept is (0,6) and the second pts are (5,7). I used this formula M = y^2 - y^1/x^2-x^1
So 7 - 6 / 5 - 0 = 1 / 0. Is this slope undefined???
You're right on the first one, but the slope on the second would be 1/5 because 5-0 is 5, not zero.
If you come across a slope with the denominator of zero though, it will be undefined.
oh yes!! ur right. my mistake...thank u so much :)
In the first question, you are correct. The slope of the equation y = -10/3x - 9/2 is -10/3 because it is the coefficient of x, which represents the rate of change of the line. And the y-intercept is (0, -9/2), which is the point where the line intersects the y-axis.
Now, let's move on to the second question. To find the slope of a graph given two points, you can use the formula:
M = (y2 - y1) / (x2 - x1)
Using the points (0, 6) and (5, 7), let's plug in these values into the formula:
M = (7 - 6) / (5 - 0)
M = 1 / 5
Therefore, the slope is 1/5.
The slope is not undefined in this case. When the denominator (x2 - x1) is zero, it suggests that the two points lie on a vertical line, which does not have a defined slope. However, in this scenario, the denominator is not zero, so the slope is well-defined and equal to 1/5.