Consider a bowl containing 36 different slips of paper. Ten of the slips of paper contain one of the set of digits 0 through 9 and 26 slips contain one of the 26 letters of the alphabet. Determine the probability of drawing one slip, what is P (even number or a vowel)

I have 5 even numbers (including 0) and 5 vowels. Would the probability be 5/36+5/36=10/36=5/18?

Even numbers = 2, 4, 6 or 8 = 4/36

Vowels = a, e, i, o, u, y = 6/36

Either-or P = sum of individual Ps

The second problem is unclear. 0 is not an even number. Are the slips being replaced or not? Do you include y as a vowel?

With your conclusions and replacement, you are right.

To determine the probability of drawing a slip that is either an even number or a vowel, you need to calculate the number of slips that satisfy this condition and divide it by the total number of slips.

First, let's determine the number of slips that are either even numbers or vowels.

There are 5 even numbers (including 0) and 5 vowels, so the total number of slips that satisfy this condition is 5 + 5 = 10.

Now, let's calculate the total number of slips in the bowl. There are 10 slips with digits 0 through 9 and 26 slips with letters of the alphabet, giving a total of 10 + 26 = 36 slips.

Finally, divide the number of slips that are either an even number or a vowel (10) by the total number of slips (36) to find the probability:

P(even number or a vowel) = 10/36 = 5/18

So, the probability of drawing a slip that is either an even number or a vowel is 5/18.