A man is pulling on a rope with a force of 53 N
directed at an angle of 70◦ to the horizontal.
What is the x-component of this force?
Answer in units of N.
53 cos70 = 18.13 N
Thanks drwls
my question is A man is pulling on a rope with a force of 52 N
directed at an angle of 55◦
to the horizontal.
What is the x-component of this force?
Answer in units of N.
cos 55 = x-component/52
x = 52 cos55
x = 29.83
To find the x-component of the force, we need to use trigonometric functions. The x-component (horizontal component) of a force can be determined using the cosine function.
The formula to find the x-component of a force is:
x-component = force * cos(angle)
In this case, the force is given as 53 N and the angle is 70 degrees.
So, to find the x-component of the force, we multiply the force (53 N) by the cosine of the angle (70 degrees):
x-component = 53 N * cos(70 degrees)
To evaluate this expression, we can use a calculator. Evaluating it, the x-component comes out to be approximately 17.81 N.
Therefore, the x-component of the force is 17.81 N.