How would you prepare 150.0 mL of a 0.200 M aqueous solution of potassium chloride from a 0.500 M aqueous solution of potassium chloride?
mL x M = mL x M
To prepare a 0.200 M aqueous solution of potassium chloride using a 0.500 M solution, you will need to dilute the 0.500 M solution with water. Here are the steps to follow:
1. Determine the volume of the 0.500 M solution needed. We can use the formula:
M1V1 = M2V2
In this case, M1 = 0.500 M, V1 is unknown, M2 = 0.200 M, and V2 = 150.0 mL.
Rearrange the formula to solve for V1:
V1 = (M2 * V2) / M1
V1 = (0.200 M * 150.0 mL) / 0.500 M
V1 = 60.0 mL
So, you will need 60.0 mL of the 0.500 M solution.
2. Measure 60.0 mL of the 0.500 M solution using a graduated cylinder or pipette.
3. Transfer the 60.0 mL of the 0.500 M solution into a clean container, such as a beaker or flask.
4. Add water to the container to reach a final volume of 150.0 mL. You can use a graduated cylinder to measure the water accurately.
5. Stir the solution thoroughly to ensure proper mixing.
You have now prepared 150.0 mL of a 0.200 M aqueous solution of potassium chloride from a 0.500 M solution.
To prepare 150.0 mL of a 0.200 M aqueous solution of potassium chloride from a 0.500 M aqueous solution of potassium chloride, you can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of the initial solution (0.500 M)
V1 = volume of the initial solution (unknown)
C2 = concentration of the final solution (0.200 M)
V2 = volume of the final solution (150.0 mL)
Rearranging the formula to solve for V1, we get:
V1 = (C2V2) / C1
Substituting the given values, we have:
V1 = (0.200 M * 150.0 mL) / 0.500 M
Simplifying the equation, we have:
V1 = (0.200 * 150.0) / 0.500
V1 = 60 mL
Therefore, to prepare 150.0 mL of a 0.200 M aqueous solution of potassium chloride from a 0.500 M aqueous solution of potassium chloride, you need to measure out 60 mL of the 0.500 M solution and then dilute it with water to make a total volume of 150.0 mL.