For the reaction

3 O2(g) reverse reaction arrow 2 O3(g)

If the equilibrium mixture is analyzed and [O2(g)] is found to be 3.77*10-2 M, what is the concentration of O3(g) in the mixture?

To find the concentration of O3(g) in the mixture, we can start by using the balanced equation of the reaction. From the equation,

3 O2(g) ⇌ 2 O3(g)

we can see that for every 3 moles of O2, we form 2 moles of O3. This means that the stoichiometric ratio between O2 and O3 is 3:2.

Given that the equilibrium concentration of O2 (represented as [O2]) is 3.77 × 10^-2 M, we can use this information to determine the concentration of O3.

Since the stoichiometric ratio between O2 and O3 is 3:2, we can set up a proportion to find the concentration of O3:

([O3]/[O2]) = (2/3)

Substituting the given value into the equation, we have:

([O3]/(3.77 × 10^-2 M)) = (2/3)

We can now solve for [O3]. Rearranging the equation, we have:

[O3] = (2/3) × (3.77 × 10^-2 M)

Calculating this expression, we find the concentration of O3 in the mixture.