f(x)=3x+1 g(x)= -4
h(x)=5x m(x)=x^2
What is m(x)/ h(x) ?
What is f ^-1(x) ?
What is h(h(x)) ?
m(x)/h(x) = x^2/(5x) = x/5
f^-1(x) is the operation performed on
f(x) = 3x +1 to get x. That would be
x = [f(x)-1]/3
You write the inverse funtion as
f^-1(x)= (x-1)/3
h(h(x) = 5*(5x) = 25x