calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from

n=5 to n=1
how do I do this?

E = 2.180E-18 J*(1/1^2 - 1/5^2)

I think I am doing something wrong.

I keep coming up with 8.72x10^17 and it is telling me I am wrong.

I know D E=2.18x10^-18 x (1/1^2-1/5^2)

i think I am not doing this part right

(1/n5^2 - 1/n1^2)

2.0928 x 10(to the power of -18)

To calculate the energy of a photon emitted during a transition in a hydrogen atom, we can use the formula:

E = -13.6 * (Z^2 / n^2) electron volts (eV)

Where:
- E is the energy of the photon in eV
- Z is the atomic number, which is 1 for hydrogen
- n is the principal quantum number of the energy level of the electron undergoing the transition

In this case, the electron is transitioning from n = 5 to n = 1. Plugging these values into the formula, we get:

E = -13.6 * (1^2 / 1^2)
= -13.6 eV

Therefore, the energy of the photon emitted during this transition is -13.6 eV. The negative sign indicates that the energy is released by the atom as a photon.