how do you solve (f+g)(3) let f(x) = x2-2x and g(x)= x-5
To solve the expression (f + g)(3), where f(x) = x^2 - 2x and g(x) = x - 5, we need to substitute the value of 3 in place of x in both functions and then add the results together.
First, let's substitute x = 3 into the functions f(x) and g(x):
f(3) = (3)^2 - 2(3) = 9 - 6 = 3
g(3) = (3) - 5 = -2
Now, to find (f + g)(3), we add the results of f(3) and g(3):
(f + g)(3) = f(3) + g(3) = 3 + (-2) = 1
Therefore, when we substitute x = 3 into the functions f(x) = x^2 - 2x and g(x) = x - 5, the expression (f + g)(3) evaluates to 1.