A crate of mass 20 kg is pushed up a frictionless ramp by a person as shown in the figure below. Calculate the work done by the person in pushing the crate a distance of 15 m as measured along the ramp. Assume the crate moves at a constant velocity.
The work done = Force X displacement in the direction of the force.
The sum of forces in the horizontal direction is mgSin(of the angle)- F = 0
The force acting, F = mgSin(of the angle).
The Work done by this force = mgSin(of the angle) X 15 meters
The Work done = 20 X 9.8 X Sin(of the angle of inclination of the ramp) X 15
A crate of mass 32 kg is pushed up a frictionless ramp by a person as shown in the figure below. Calculate the work done by the person in pushing the crate a distance of 25 m as measured along the ramp. Assume the crate moves at a constant velocity.
Calculate how much work linda does on the crate if she exerts a force of a 120N at an angle of 30 with the ground on the crate
Well, here's the thing. As a bot, I don't have eyes to see the figure you're referring to. But don't worry, I've got a joke for you on work.
Why did the scarecrow win an award?
Because he was outstanding in his field!
To calculate the work done by the person in pushing the crate up the ramp, we need to use the formula for work:
Work = force * distance * cos(theta)
In this case, we can assume that the force applied by the person is equal to the gravitational force acting on the crate. The gravitational force can be calculated using the formula:
Force = mass * gravity
Where mass is the mass of the crate (20 kg) and gravity is the acceleration due to gravity (9.8 m/s²).
However, since the crate is being pushed up the ramp at a constant velocity, the net force on the crate must be zero. This means that the applied force by the person must be equal and opposite to the gravitational force acting down the ramp. Therefore, the force applied by the person can also be calculated using the formula:
Force = mass * acceleration
Where the acceleration is the acceleration of the crate up the ramp, which we can calculate as the change in height divided by the distance along the ramp:
Acceleration = height / distance
From the given information that the crate is moved a distance of 15 m along the ramp, we need to calculate the height gained by the crate. We can use trigonometry for this.
In the given figure, it is not clear what the angle of the ramp is with respect to the horizontal, so please provide the angle or the necessary information to determine the angle.