What are the solution intervals for |2x – 1| + 6 > 9?
[2x - 1] + 6 > 9.
[2x - 1] > 9 - 6,
[2x - 1] > 3,
2x - 1 > 3,
+-(2x - 1) > 3,
+(2x - 1) >3,
2x - 1 > 3,
2x > 3 + 1,
2x > 4,
x > 2.
-(2x - 1) > 3,
-2x + 1 > 3,
-2x > 3 - 1,
-2x > 2,
x < - 1.
Solutin set: - 1 > x > 2.
All real values of x less than -1 and all real values of x greater than 2 should satisfy the inequality.