A pitched ball with a mass of 1 kg reaches a catcher's glove traveling at a velocity of 28 m/s. How much momentum does the ball have? how much impulse is required to stop the ball? If the ball is in contact with the catcher's glove for 0.5 s during the catch, how much average force is applied by the glove?

To find the momentum of the ball, we can use the equation:

Momentum = mass * velocity

Given that the mass of the ball is 1 kg and the velocity is 28 m/s, we can substitute these values into the equation:

Momentum = 1 kg * 28 m/s = 28 kg·m/s

Therefore, the ball has a momentum of 28 kg·m/s.

To find the impulse required to stop the ball, we can use the equation:

Impulse = change in momentum

Since the ball is initially moving with a momentum of 28 kg·m/s, and it needs to stop, the change in momentum would be -28 kg·m/s (opposite direction).

Impulse = -28 kg·m/s

Now, let's calculate the average force applied by the glove to stop the ball. We can use the equation:

Impulse = force * time

Given that the impulse is -28 kg·m/s and the time for which the ball is in contact with the glove is 0.5 seconds, we can rearrange the equation to solve for force:

Force = impulse / time

Substituting the values, we have:

Force = (-28 kg·m/s) / (0.5 s) = -56 N

Note that the negative sign indicates that the force applied by the glove is in the opposite direction to the direction of the ball's initial motion. Therefore, the average force applied by the glove is 56 N.

To calculate the momentum of the ball, we can use the formula:

Momentum = mass * velocity

Given that the mass of the ball is 1 kg and its velocity is 28 m/s, we can substitute these values into the formula:

Momentum = 1 kg * 28 m/s = 28 kg*m/s

Therefore, the ball has a momentum of 28 kg*m/s.

Now, let's calculate the impulse required to stop the ball. Impulse is given by the formula:

Impulse = Force * time

Since the ball comes to a stop, the velocity changes from 28 m/s to 0 m/s. Therefore, the change in velocity is 28 m/s.

Using Newton's second law, we can relate impulse to the change in momentum:

Impulse = Change in Momentum

Impulse = Final Momentum - Initial Momentum

Impulse = 0 kg*m/s - 28 kg*m/s = -28 kg*m/s

Therefore, the impulse required to stop the ball is -28 kg*m/s.

Finally, we can calculate the average force applied by the glove using the formula:

Impulse = Force * time

Rearranging the formula, we get:

Force = Impulse / time

Given that the impulse is -28 kg*m/s and the time is 0.5 s, we can substitute these values:

Force = (-28 kg*m/s) / (0.5 s) = -56 N

Therefore, the average force applied by the glove is -56 N (negative indicates opposite direction of initial velocity).

A pitched ball with a mass of 1 kg reaches a catcher's glove traveling at a velocity of 28 m/s. If the ball is in contact with the catcher's glove for 0.5 s during the catch, how much average force is applied by the glove?

56
A pitched ball with a mass of 1 kg reaches a catcher's glove traveling at a velocity of 28 m/s. How much momentum does the ball have?
28
A pitched ball with a mass of 1 kg reaches a catcher's glove traveling at a velocity of 28 m/s. How much impulse is required to stop the ball?
28