chemistry

A chemist wants to make 5.5 L of a 0.250 M CaCl2 solution, what mass of CaCl2 (in g) should the chemist use?

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  1. massCaCL2=molarity*volume*molmassCaCl2

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    bobpursley
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  3. M = 0.250 mols/L * (111g CaCl2/1 mols CaCl2)= 27.7g/L
    n = M*L
    n = (27.7g/L)*(5.5L)= 153g of CaCl2

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