# chemistry

A chemist wants to make 5.5 L of a 0.250 M CaCl2 solution, what mass of CaCl2 (in g) should the chemist use?

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3. 👁 1,215
1. massCaCL2=molarity*volume*molmassCaCl2

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👨‍🏫
bobpursley
2. Wha??

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3. M = 0.250 mols/L * (111g CaCl2/1 mols CaCl2)= 27.7g/L
n = M*L
n = (27.7g/L)*(5.5L)= 153g of CaCl2

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