I need to write a net ionic equation for Sr{2+}+ Hg2 + NaCL =
I assume the Hg2 is the mercuryII ion, Hg++
Hg++ + 2Cl- >> HgCl2 (s)
To write the net ionic equation, we first need to write the balanced molecular equation for the given reaction.
The given reaction is:
Sr^(2+) + Hg2 + NaCl ->
Next, we need to identify the ions present in the reactants by looking at their charges. The ions present are Sr^(2+), Hg2^(2+), Na^(+), and Cl^(-).
Now, let's write the balanced molecular equation:
Sr^(2+) + Hg2 + 2NaCl -> SrCl2 + Hg2 + 2Na^(+)
To write the net ionic equation, we need to eliminate the spectator ions, which are the ions that appear on both sides of the equation without undergoing a chemical change. In this case, the spectator ions are Na^(+) and Cl^(-).
The net ionic equation is obtained by removing the spectator ions:
Sr^(2+) + Hg2 -> SrCl2 + Hg2
Therefore, the net ionic equation for the given reaction is Sr^(2+) + Hg2 -> SrCl2 + Hg2.