a sample of unknown gas is found to have a volume of 479 mL at 27.0 degrees C and 1.30 atm. How may moles of gas are int eh sample?
PV = nRT
Solve for n.
pv/rt=n
To determine the number of moles of gas in the sample, we can use the ideal gas law, which states that PV = nRT, where P is the pressure in atmospheres (atm), V is the volume in liters (L), n is the number of moles, R is the ideal gas constant (0.0821 L*atm/mol*K), and T is the temperature in Kelvin (K).
First, let's convert the given volume from milliliters (mL) to liters (L):
479 mL = 479/1000 = 0.479 L
Next, we need to convert the temperature from Celsius (°C) to Kelvin (K). The formula to convert is: K = °C + 273.15
T = 27.0 + 273.15 = 300.15 K
Now, we can plug the values into the equation and solve for n:
P = 1.30 atm
V = 0.479 L
T = 300.15 K
R = 0.0821 L*atm/mol*K
PV = nRT
(1.30 atm)(0.479 L) = n(0.0821 L*atm/mol*K)(300.15 K)
Simplifying the equation:
0.6277 = 24.623715n
To solve for n, divide both sides of the equation by 24.623715:
n = 0.6277 / 24.623715
Calculating the value:
n ≈ 0.0255 moles
Therefore, there are approximately 0.0255 moles of gas in the sample.