There are four tests in a year. The first test is worth 26%, the second is worth 20%, the third test is worth 30%, and the fourth test is 20%. Maria received a 59% on her first test. To receive a final mark of 65%, what is the minimum she needs to obtain on each test?
Can someone please explain to me how I would do this? Thank you!
Your percentages don't add up to 100%. Please check your data and post any corrections.
Opps, sorry.. I forgot to write that Maria also has a project worth 4% which she got perfect on
To determine the minimum mark Maria needs to obtain on each remaining test, we can follow these steps:
Step 1: Calculate the current weightage of the first test:
Multiply the mark Maria received on the first test (59%) by its weightage (26%) and divide by 100:
Current Weightage = (59 * 26) / 100 = 15.34
Step 2: Calculate the remaining weightage:
Subtract the current weightage from the target final mark (65%):
Remaining Weightage = 65 - 15.34 = 49.66
Step 3: Distribute the remaining weightage across the three tests:
Since the second, third, and fourth tests have a combined weightage of 70%, divide the remaining weightage (49.66) by 70 and multiply by 100 to get the minimum mark Maria needs to obtain on each test.
For the second test:
Second Test Weightage = (49.66 * 20) / 70 = 14.19
For the third test:
Third Test Weightage = (49.66 * 30) / 70 = 21.36
For the fourth test:
Fourth Test Weightage = (49.66 * 20) / 70 = 14.19
Therefore, Maria needs to obtain a minimum of 14.19% on the second, third, and fourth tests to achieve a final mark of 65%.