1. A vector has (at minimum) how many parts associated with it?

2. When adding three vectors graphically one needs to:

a. Spin each one like a spinner on a board game.
b. Do nothing because more than two vectors cannot be added graphically
c. draw all the tails at the same point.
d. draw the next vector's tail on the previous vecotr's head
e. draw the next vector's head on the previous vector's tail

1. Two

2. d. draw the next vector's tail on the previous vector's head

To solve the first question, about the minimum number of parts associated with a vector, we can use our understanding of vectors. A vector is a mathematical object that has both magnitude (size or length) and direction. In order to specify its direction, we need to refer to a coordinate system or a reference point.

For example, in a two-dimensional space, we often use the x and y coordinates to describe the position of a vector. This means that a vector in 2D space will have two parts associated with it, one for the x-coordinate and one for the y-coordinate.

Similarly, in a three-dimensional space, we would need three parts to describe a vector, one for each of the x, y, and z coordinates.

Now, let's move on to the second question, which involves adding three vectors graphically. Graphically adding vectors involves representing each vector as an arrow and then combining them to find the resultant vector. To do this, we follow a specific method:

d. draw the next vector's tail on the previous vector's head.

Here's the step-by-step process:

1. Draw the first vector as an arrow, starting at the origin or any chosen point.
2. Draw the second vector as an arrow, with its tail starting at the head of the first vector.
3. Draw the third vector as an arrow, with its tail starting at the head of the second vector.
4. The resultant vector is then drawn from the tail of the first vector to the head of the third vector. This represents the combined effect of all three vectors.

By following this process, we can accurately add three vectors graphically.