if it requires 35.0 milliliters of 0.50 molar NaOH to neutralize 25.0 milliliters of HCl, what is the concentration of the HCl solution?
Balanced equation: NaOH + HCl yields NaCl + H2O
For a 1:1 reaction, the simple equation of
mL x M = mL x M will do.
If it requires 35.0 milliliters of 0.50 molar NaOH to neutralize 25.0 milliliters of HCl, what is the concentration of the HCl solution?
Balanced equation: NaOH + HCl yields NaCl + H2O (3 points) 0.36 M HCl
0.70 M HCl
1.1 M HCl
1.4 M HCl
GOOD JOIB BABY
To determine the concentration of the HCl solution, you can use the concept of stoichiometry and the given information.
First, let's convert the volume of the NaOH solution from milliliters to liters:
35.0 milliliters = 35.0/1000 liters = 0.035 liters
Next, you need to calculate the number of moles of NaOH used. To do this, you can use the equation: moles = concentration × volume. In this case, the concentration of NaOH is 0.50 molar, and the volume is 0.035 liters.
moles of NaOH = 0.50 mol/L × 0.035 L = 0.0175 moles
According to the balanced equation, the ratio of moles of NaOH to HCl is 1:1. Therefore, the moles of HCl used are also equal to 0.0175 moles.
Now, we can calculate the concentration of the HCl solution. The concentration of a solution is expressed as moles of solute per liter of solution. In this case, the volume of the HCl solution is 25.0 milliliters, which can be converted to liters by dividing by 1000:
25.0 milliliters = 25.0/1000 liters = 0.025 liters
Concentration of HCl = moles of HCl / volume of HCl solution
Concentration of HCl = 0.0175 moles / 0.025 liters = 0.70 mol/L (or 0.70 M)
Therefore, the concentration of the HCl solution is 0.70 molar (0.70 M).