If 10.00 g of C2H2 is mixed with 80.0 g of Br2, what masses of C2H2Br2 and C2H2Br4 will be formed? Assume that all the C2H2 has reacted.
what is mass of n2cro4
To determine the masses of C2H2Br2 and C2H2Br4 formed, we need to calculate the limiting reactant first, which is the reactant that is completely consumed and determines the maximum amount of product that can be formed.
Step 1: Determine the molar masses of C2H2, Br2, C2H2Br2, and C2H2Br4.
- The molar mass of C2H2 (acetylene) is:
C: 12.01 g/mol × 2 = 24.02 g/mol
H: 1.01 g/mol × 2 = 2.02 g/mol
Total: 24.02 g/mol + 2.02 g/mol = 26.04 g/mol
- The molar mass of Br2 (bromine) is:
Br: 79.90 g/mol × 2 = 159.80 g/mol
- The molar mass of C2H2Br2 (dibromoethene) is:
C: 12.01 g/mol × 2 = 24.02 g/mol
H: 1.01 g/mol × 2 = 2.02 g/mol
Br: 79.90 g/mol × 2 = 159.80 g/mol
Total: 24.02 g/mol + 2.02 g/mol + 159.80 g/mol = 185.84 g/mol
- The molar mass of C2H2Br4 (tetrabromoethane) is:
C: 12.01 g/mol × 2 = 24.02 g/mol
H: 1.01 g/mol × 2 = 2.02 g/mol
Br: 79.90 g/mol × 4 = 319.60 g/mol
Total: 24.02 g/mol + 2.02 g/mol + 319.60 g/mol = 345.64 g/mol
Step 2: Calculate the number of moles for C2H2 and Br2 using their respective molar masses and given masses.
- Moles of C2H2 = Given mass of C2H2 / Molar mass of C2H2
= 10.00 g / 26.04 g/mol
- Moles of Br2 = Given mass of Br2 / Molar mass of Br2
= 80.0 g / 159.80 g/mol
Step 3: Determine the limiting reactant by comparing the mole ratios of C2H2 and Br2.
The balanced chemical equation for the reaction is:
C2H2 + Br2 → C2H2Br2 + C2H2Br4
From the equation, we can see that the mole ratio between C2H2 and C2H2Br2 is 1:1, and the mole ratio between C2H2 and C2H2Br4 is 1:2.
- Moles of C2H2Br2 formed = Moles of C2H2
- Moles of C2H2Br4 formed = 2 × Moles of C2H2
Step 4: Calculate the masses of C2H2Br2 and C2H2Br4 formed using their respective mole ratios and molar masses.
- Mass of C2H2Br2 formed = Moles of C2H2Br2 × Molar mass of C2H2Br2
- Mass of C2H2Br4 formed = Moles of C2H2Br4 × Molar mass of C2H2Br4
Finally, substitute the values obtained from the previous steps into the equations to find the masses of C2H2Br2 and C2H2Br4.