Written out, would the reaction between anihiline [C6H5NH2] and perchloric acid look like this:

C6H5NH2 + HClO4 -> C6H5ClO4 + HNH2

?

The NH2 group on aniline is basic. It takes on a H^+ from HClO4 and forms the salt. The salt is C6H5NH3^+ + ClO4^-. I hope this helps.

Yes

The given reaction between aniline (C6H5NH2) and perchloric acid (HClO4) does not correctly represent the reaction between these two compounds. The correct reaction between aniline and perchloric acid would look like this:

C6H5NH2 + HClO4 -> C6H5NH3+ClO4-

Let me explain how I obtained this balanced chemical equation.

When aniline reacts with perchloric acid, the NH2 group on aniline, which acts as a base, reacts with the acid to form a salt. In this case, the base accepts a proton (H+) from the acid, resulting in the formation of C6H5NH3+ (anilinium ion) and ClO4- (perchlorate ion).

To balance the equation, we need to ensure that the number of atoms on both sides of the equation is the same. In this case, the only atoms that need to be balanced are carbon (C), hydrogen (H), nitrogen (N), and oxygen (O).

On the left-hand side of the equation, we have one carbon atom, eight hydrogen atoms, one nitrogen atom, and four oxygen atoms. On the right-hand side, we have the same number of atoms since they are part of the same molecules.

Therefore, the balanced chemical equation for the reaction between aniline and perchloric acid is:

C6H5NH2 + HClO4 -> C6H5NH3+ClO4-

The reaction between aniline (C6H5NH2) and perchloric acid (HClO4) can be written as follows:

C6H5NH2 + HClO4 -> C6H5NH3+ClO4-

In this reaction, the acidic proton from perchloric acid (HClO4) is transferred to the amino group (NH2) of aniline, resulting in the formation of the anilinium cation (C6H5NH3+) and the perchlorate anion (ClO4-).