The specific heat of ice is 0.5 calories/gram.
60 grams of ice will require _____ calories to raise the temperature 1°C.
so i just do 0.5/60 ??
You use those numbers but not that way.
mass ice x specific heat ice x (Tfinal-Tinitial).
60 g x 0.5 cal/g x (1) = ??
and I got 30.
correct?
i got 30
right.
thank you
To calculate the number of calories required to raise the temperature of 60 grams of ice by 1°C, you'll need to use the formula:
Q = m * c * ΔT
where:
Q is the energy (in calories) required,
m is the mass (in grams) of the substance,
c is the specific heat capacity (in calories/gram °C) of the substance, and
ΔT is the change in temperature (in °C).
In this case, you have:
m = 60 grams
c = 0.5 calories/gram
ΔT = 1°C
Substituting these values into the formula, you get:
Q = 60 * 0.5 * 1
Simplifying the equation:
Q = 30 calories
So, 60 grams of ice will require 30 calories to raise the temperature by 1°C. Therefore, the correct calculation would be:
30 calories.