what is the balanced molecular equation and their physical state of each substance for: copper(II) sulfate and 10% sodium hydroxide?

I am not sure that I understand the question. Are you looking for the equation for the reaction between copper(II) sulfate and 10% sodium hydroxide, including the state (phase) symbols?

yes. the reactant of those two and the product

To determine the balanced molecular equation and the physical state of each substance for the reaction between copper(II) sulfate and 10% sodium hydroxide, follow these steps:

Step 1: Write the chemical formula for each compound:
Copper(II) sulfate is CuSO4
Sodium hydroxide is NaOH

Step 2: Determine the products of the reaction:
Copper(II) sulfate reacts with sodium hydroxide to form copper(II) hydroxide and sodium sulfate.

Step 3: Write the balanced molecular equation:
CuSO4 + 2NaOH -> Cu(OH)2 + Na2SO4

Step 4: Assign the physical state of each substance:
Since copper(II) sulfate is usually a solid (CuSO4), it will be denoted as (s) for solid.
Sodium hydroxide is typically a 10% aqueous solution, which means it is dissolved in water. Thus, it will be denoted as (aq) for aqueous.
Copper(II) hydroxide is a light blue precipitate, so it will be denoted as (s) for solid.
Sodium sulfate is also an aqueous solution, so it will be denoted as (aq) for aqueous.

Therefore, the balanced molecular equation with the physical states is:
CuSO4(s) + 2NaOH(aq) -> Cu(OH)2(s) + Na2SO4(aq)

Note: The physical states of the substances may vary depending on the specific conditions of the reaction.