How many mL of a 0.217 M aqueous solution of ammonium fluoride, NH4F, must be taken to obtain 3.63 grams of the salt?

Start from calculating the molar mass of NH4F, F.

we need therefore, 3.63/F moles of ammonium fluoride.

The solution contains 0.217 M, or 0.217 moles in 1 litre.

which is 1000/0.217 ml mole^-1

hence volume required is

(1000/0.217 ml mole^-1)x (3.63/F moles )

To solve this problem, we need to use the equation relating the amount of solute, concentration of the solution, and the volume of the solution.

The equation is:
Amount of solute = Concentration of the solution × Volume of the solution

Let's calculate it step by step:

Step 1: Determine the molar mass of ammonium fluoride (NH4F).
The molar mass of NH4F is calculated by adding the molar masses of its components:
Molar mass of NH4F = Molar mass of NH4 + Molar mass of F
= (1 × molar mass of H) + (4 × molar mass of H) + (1 × molar mass of F)

From the periodic table, you can find that:
Molar mass of H = 1.01 g/mol
Molar mass of F = 18.99 g/mol

Calculating further, we have:
Molar mass of NH4F = (1 × 1.01) + (4 × 1.01) + 18.99
= 18.04 g/mol

Step 2: Calculate the amount of solute (NH4F) in grams.
The given amount of NH4F is 3.63 grams.

Step 3: Calculate the number of moles of NH4F.
The number of moles of NH4F is calculated using the formula:
Number of moles = mass / molar mass
= 3.63 g / 18.04 g/mol

Step 4: Calculate the volume of the solution.
We are given the concentration (0.217 M) and we want to find the volume of the solution in milliliters (mL).
The equation for calculating the volume is:
Volume of the solution = Amount of solute / Concentration of the solution

Substituting the values, we have:
Volume of the solution = (3.63 g / 18.04 g/mol) / 0.217 mol/L

Step 5: Convert the volume to milliliters (mL).
Since the volume is given in molar units (L), we need to convert it to milliliters by multiplying by 1000.
Volume of the solution in mL = (3.63 g / 18.04 g/mol) / 0.217 mol/L × 1000 mL/L

Calculating further, we get:
Volume of the solution = 870 mL (rounded to the nearest whole number)

Therefore, to obtain 3.63 grams of ammonium fluoride (NH4F) in a 0.217 M solution, you would need to take approximately 870 mL of the solution.