An object is solid throughout. When the object is completely submerged in ethanol alcohol., its apparent weight is 15.2 N. When completely submerged in water, its weight is 13.7 N. What is its volume? Steps please.. answer isnt really necessary
To find the volume of the object, you can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
Here are the steps:
Step 1: Calculate the weight of the object in air.
Given that the apparent weight of the object when submerged in ethanol alcohol is 15.2 N, this is also its weight in air.
Step 2: Calculate the weight of the object when submerged in water.
Given that the weight of the object when submerged in water is 13.7 N, subtract this weight from the weight in air.
Weight in air - Weight in water = Weight of the displaced fluid
15.2 N - 13.7 N = 1.5 N
Step 3: Calculate the weight of the displaced fluid.
Since the weight of the displaced fluid is equal to the buoyant force, which is also equal to the weight of the object, you can conclude that the weight of the displaced fluid is 1.5 N.
Step 4: Use the density of water to find the volume of the displaced fluid.
Since the object is completely submerged in water, the displaced fluid is water. The density of water is approximately 1000 kg/m³ (or 1000 g/cm³).
Density = Mass / Volume
Rearranging the equation: Volume = Mass / Density
Since the weight of the displaced fluid is equal to its mass multiplied by the acceleration due to gravity, we have:
Weight = Mass * g
Solving for Mass: Mass = Weight / g
Mass = 1.5 N / 9.8 m/s² ≈ 0.153 kg
Now, by using the density formula, we can calculate the volume:
Volume = Mass / Density
Volume = 0.153 kg / 1000 kg/m³ ≈ 0.000153 m³ or 153 cm³
Therefore, the volume of the object is approximately 0.000153 m³ or 153 cm³.