10.0 mL of 0.15M of sulfuric acid is titrated with 0.05M of sodium hydroxide. how many mL of sodium hydroxide solution are required to reach the equivalence point?

Start from a balanced equation

NaOH + H2SO4 -> Na2SO4 + H2O

you need to balance this.

10.0 x 0.15 = mmoles of H2SO4

the balanced equation will tell you how many moles of NaOH react with each moles of H2SO4

calculate the number of mmoles (X) of NaOH needed

hence volume needed = X/0.05

To find the volume of sodium hydroxide solution required to reach the equivalence point in this titration, we need to use the concept of stoichiometry and the balanced chemical equation for the reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH).

The balanced chemical equation for the reaction is as follows:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O

From the balanced equation, we can see that the stoichiometric ratio between sulfuric acid and sodium hydroxide is 1:2. This means that one mole of sulfuric acid reacts with two moles of sodium hydroxide.

First, let's calculate the number of moles of sulfuric acid present in the given volume (10.0 mL) and concentration (0.15 M). To do this, we will use the formula:

moles = volume (in liters) x concentration (in mol/L)

Given:
Volume of sulfuric acid = 10.0 mL = 0.0100 L
Concentration of sulfuric acid = 0.15 M

moles of sulfuric acid = 0.0100 L * 0.15 mol/L
= 0.0015 mol

Since the stoichiometric ratio between sulfuric acid and sodium hydroxide is 1:2, we need twice the number of moles of sodium hydroxide to neutralize sulfuric acid.

moles of sodium hydroxide required = 2 * 0.0015 mol
= 0.0030 mol

Now, let's find the volume of sodium hydroxide solution needed to reach the equivalence point using the given concentration of 0.05 M.

moles = volume (in liters) x concentration (in mol/L)

Given:
Concentration of sodium hydroxide = 0.05 M

0.0030 mol = volume (in liters) * 0.05 mol/L

volume (in liters) = 0.0030 mol / 0.05 mol/L
= 0.06 L

Finally, let's convert the volume from liters to milliliters:

volume (in mL) = 0.06 L * 1000 mL/L
= 60 mL

Therefore, 60 mL of sodium hydroxide solution are required to reach the equivalence point in this titration.