The lcm of two #s is 60. one of the #s is 20. other # is even & has only two prime factors. what is the other number?
To find the other number, we need to determine its prime factors and find the factorization that satisfies the given conditions.
Given that the LCM (Least Common Multiple) of two numbers is 60 and one of the numbers is 20, we can use the fact that the LCM is the product of the numbers divided by their greatest common divisor (GCD).
We know one of the numbers is 20, so let's find the GCD between 20 and the unknown number. The GCD of two numbers is the largest number that divides both numbers evenly.
Let's find the prime factors of 20. We can factorize 20 into its prime factors: 20 = 2^2 * 5.
Now, let's consider the possible options for the other number. We are looking for an even number with two prime factors.
The prime factors of the other number should be distinct prime numbers and their product should be 60/20 = 3. The only possibility is 2 and 3.
Therefore, the other number must be (2 * 3) = 6.
So, the other number is 6.