I am having trouble with the following problem:
P(Z > +1.34)
Would someone help me?
If you've already normalized the number you're interested in, then look up in your tables (the normal distribution tables) to find 1.34 standard deviations and look for the probability associated with it.
According to my calculator the probability a normally distributed observation is greater than 1.34 standard deviations of the norm is .090123
Thank you for the help!
To solve the problem, P(Z > +1.34), you need to find the probability that a standard normal distribution (Z) is greater than 1.34.
To find this probability, you can use the standard normal distribution tables or a calculator that has a built-in function for calculating the probabilities associated with the standard normal distribution.
If you are using standard normal distribution tables, you need to find the value closest to 1.34 in the table and then look up the corresponding probability.
1. Locate the row in the table that contains the tenths place value of 1.34, which is 1.3.
2. In this row, find the column that corresponds to the hundredths place value of 1.34, which is 0.04.
3. The intersection of 1.3 and 0.04 in the table will give you the probability associated with this value, which is 0.908. However, since we want P(Z > +1.34), we need to subtract this value from 1.
4. Subtract 0.908 from 1 to get the probability of P(Z > +1.34), which is approximately 0.092.
Alternatively, if you have a calculator that can calculate probabilities for the standard normal distribution, you can directly input the value 1.34 and find the probability associated with it.
Using this method, you input 1.34 into the calculator and look for the probability associated with P(Z > 1.34). According to your calculator, the probability is approximately 0.090123.
So, the answer to the problem P(Z > +1.34) is approximately 0.090123, as calculated by your calculator.
I hope this explanation helps! Let me know if you have any further questions.