Chemistry

A sample of 1.029g of KC8H5O4 was titrated with an NAOH solution of unknown concentration. If 22.83 mL of base was used to reach the endpoint, what was the concentration of NaOH? What mass of KC8H5O4 should be used such that a volume of NaOH between 35-40 mL is needed to reach the endpoint?

Please help, I procrastinated and its due tomorrow!!!

  1. 👍
  2. 👎
  3. 👁
  1. You probably intended this to be potassium hydrogen phthalate which I will rewrite, to make things simpler, as KHP. The H is the hydrogen neutralized by the NaOH.
    NaOH + KHP ==> NaKP + H2O.
    mols KHP = 1.029 grams/molar mass KHP.
    mols NaOH = mols KHP.
    mols NaOH = L x M. You know mols and you know L. M is the only unknown.

    The second part of the problem is done by working backwards. Using the molarity of the NaOH calculated above, use mols = L x M and plug in , say 38 mL (0.038 L or about half way between 35 and 40). That allows you to calculate mols. Then use mols KHP and mols KHP = grams/molar mass. You know mols KHP and you know molar mass so calculate grams KHP.

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. chemistry

    CH3NH2(aq)+H2O(l)=>CH3NH3+(aq)+OH-(aq) Kb=4.4 x 10^-4 Methylamine, CH3NH2, is a weak base that reacts with water according to the equation above. A student obtains a 50.0 mL sample of a methylamine solution and determines the pH

  2. chemistry

    When the glucose solution described in part A is connected to an unknown solution via a semipermeable membrane, the unknown solution level rises. Based on this information, what can be said about these two solutions? a.) The

  3. AP Chemistry

    CH3NH2(aq)+H2O(l)=>CH3NH3+(aq)+OH-(aq) Kb=4.4 x 10^-4 Methylamine, CH3NH2, is a weak base that reacts with water according to the equation above. A student obtains a 50.0 mL sample of a methylamine solution and determines the pH

  4. Chemistry

    Commercial vinegar was titrated with NaOH solution to determine the content of acetic acid, HC2H3O2. For 20.0 milliliters of the vinegar 26.7 milliliters of 0.600-molar NaOH solution was required. What was the concentration of

  1. Chemistry

    One commercial method used to peel potatoes is to soak them in a solution of NaOH for a short time, remove them from the NaOH, and spray off the peel. The concentration of NaOH is normally in the range of 3 to 6 M. The NaOH is

  2. chemistry

    A 27.00 mL sample of an unknown H3PO4 solution is titrated with a 0.110 M NaOH solution. The equivalence point is reached when 25.78 mL of NaOH solution is added. What is the concentration of the unknown H3PO4 solution? The

  3. chemistry

    A 25 mL solution of .5M NaOH is titrated until neutralization into a 50mL sample of HCl. What was the concentration of HCl?

  4. chem-please help!!!!!

    when a 25.0 mL sample of an unknown acid was titrated with a 0.100 M NaOH solution. Determine Ka for the unknown acid. Volume NaOH = 25 mL; pH=8.25

  1. Chemistry

    1. You have been given a sample of unknown molarity. Calculate the molarity of a solution which has been prepared by dissolving 8.75 moles of sodium chloride in enough water to produce a solution of 6.22l. 2. You have a sample

  2. Chemistry

    A sample of oxalic acid, H2C2O4, is titrated with standard sodium hydroxide, NaOH, solution. A total of 45.2 mL of 0.12 M NaOH is required to completely neutralize 20.0 mL of the acid. What is the concentration of the acid?

  3. Chemistry

    40.0 ml of an acetic acid of unknown concentration is titrated with 0.100 M NaOH. After 20.0 mL of the base solution has been added, the pH in the titration flask is 5.10. What was the concentration of the original acetic acid

  4. Chemistry

    For my lab, I have been asked to calculate the pKa of an unknown amino acid. We titrated the unknown amino acid with NaOH. The pKa needs to be calculated using the Henderson Hasselbach Equation. Obviously you can just get the pH

You can view more similar questions or ask a new question.