2NH3(g)+3CuO(s)=N2(g)+3Cu(s)+3H2O(g)

if 18.1grams of ammonia reacts with 90.4 grams of copper(II) oxide, which is the limitting reagent?? what is the theorectical yield of nitrogen gasd? if 8.52 g of N2 are formed, what is the % yield of nitrogn gas??

please check if is correct....
A)
18.1gNH3(1 mol NH3/17.03gNH3)(1molN2/2molNH3)= .053 mol N2

90.4gCuO (1molCuO/79.55gCuO) (1molN2/3molCuO)= .379N2, so CuO is the L.R.
B)
0.379molN2 x 28.02gN2/1mol N2= 10.62gN2, ***so, 10.62g N2 is the theoretical yield.
C)
8.52gN2/10.62gN2 x 100= 80.2% yield of N2
please check if I'm doing this problem correct...thankx...

You made a typo for A, it should be 0.053.

For B, I used 28.01 for molar mass N2 and obtained an answer of 10.61 for g N2.
Then 8.52/10.61 *100 = 80.28 which I rounded to 80.3.
Your method is fine. My source for molar mass may be incorrect. I didn't add all of those number myself. Here is the site I used.
http://environmentalchemistry.com/yogi/reference/molar.html#Calculator

a. OK, except the decimal is wrong, typo

b. ok
c. correct.

Thank u!!!!

Your calculations and reasoning are correct. Let's review the steps:

A) To determine the limiting reagent, you need to convert the mass of each reactant to moles and compare the mole ratios in the balanced equation.

For ammonia (NH3):
18.1g NH3 * (1 mol NH3 / 17.03g NH3) * (1 mol N2 / 2 mol NH3) = 0.053 mol N2

For copper(II) oxide (CuO):
90.4g CuO * (1 mol CuO / 79.55g CuO) * (1 mol N2 / 3 mol CuO) = 0.379 mol N2

Since ammonia produces 0.053 mol N2 and copper(II) oxide produces 0.379 mol N2, we can see that ammonia is the limiting reagent because it produces fewer moles of N2.

B) To calculate the theoretical yield of nitrogen gas (N2), you need to multiply the mole amount of N2 with its molar mass.

0.379 mol N2 * (28.02g N2 / 1 mol N2) = 10.62g N2

So, the theoretical yield of N2 is 10.62 grams.

C) To calculate the percent yield of N2, divide the actual yield (8.52g N2) by the theoretical yield (10.62g N2) and multiply by 100.

(8.52g N2 / 10.62g N2) * 100 = 80.2% yield of N2

Therefore, your answers are correct. Well done!