What is the molarity of a 1.4% HCOOH solution
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To find the molarity of a solution, you need to know the concentration of the solute and the volume of the solution. In this case, we have a 1.4% HCOOH solution.
Step 1: Convert the given percentage to decimal form.
The percentage is given as 1.4%. To convert it to decimal form, divide it by 100:
1.4% / 100 = 0.014
Step 2: Determine the molar mass of HCOOH.
The molar mass of HCOOH (formic acid) can be calculated by summing the atomic masses of its constituent elements:
H: 1.008 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
HCOOH (formic acid) has one carbon (C) atom, two oxygen (O) atoms, and two hydrogen (H) atoms.
Molar mass = (1 * 12.01) + (2 * 1.008) + (2 * 16.00) = 46.03 g/mol
Step 3: Calculate the molarity.
The molarity is defined as the number of moles of solute per liter of solution. Since we have a 1.4% solution, it means 1.4 grams of HCOOH is present in 100 mL (or 0.1 L) of solution.
First, calculate the number of moles of HCOOH:
moles = mass / molar mass
moles = 0.014 g / 46.03 g/mol = 0.000303 mol
Then, calculate the molarity:
molarity = moles / volume
volume = 0.1 L
molarity = 0.000303 mol / 0.1 L = 0.00303 M
So, the molarity of a 1.4% HCOOH solution is approximately 0.00303 M.