using ratio 1:2 find the perimeter of rectangle that has a width of 6 inches and a length of 8 inches? need answer asap

I think something is missing in your question. The perimeter is found by adding L +W +L+W= 8+6+8+6=28 inches.

If trying to find dimension of another rectangle which is in ratio 1:2 then the parameter of that second rectangel will be twice , that is 56 inches, and its dimention twice that is lenth 16 inches and width 12 inches.

Thank you I came to the same conclusion

I just wanted to see if I was going in the right direction

To find the perimeter of a rectangle, you need to add up all four sides.

In this case, the ratio of the length to the width is given as 1:2. Let's assign a variable to represent the common factor in this ratio. Let's call it "x". Therefore, the length would be x inches and the width would be 2x inches.

It is also given that the width is 6 inches, so we can set up an equation to find the value of x:

2x = 6

To solve for x, divide both sides of the equation by 2:

x = 6/2
x = 3

Now that we know the value of x, we can substitute it back into the formula for the width and length:

Length = x = 3 inches
Width = 2x = 2 * 3 = 6 inches

To find the perimeter, add up all four sides:

Perimeter = 2 * (Length + Width)
Perimeter = 2 * (3 + 6)
Perimeter = 2 * 9
Perimeter = 18 inches

Therefore, the perimeter of the rectangle is 18 inches.