This question really has me stumped and I don't know why, I seem to have forgotten the process . . .
A model electric train requires 6 V to operate. If the primary coil of its transformer has 240 windings, how many windings should the secondary have if the primary is connected to a 120 V household circuit?
6/120 = N/240
solve for n.
Is this it?
6/120 = N/240 (240) 6/120 = n/240 (240)
12 = N
To solve this problem, you can use the formula for voltage transformation in a transformer:
(Vp/Np) = (Vs/Ns)
Where:
Vp = Primary voltage
Np = Number of windings in the primary coil
Vs = Secondary voltage
Ns = Number of windings in the secondary coil
In this case, since the primary voltage (Vp) is 120 V, the number of windings in the primary coil (Np) is 240, and the operating voltage for the electric train (Vs) is 6 V, we need to find the number of windings in the secondary coil (Ns).
Plugging in the given values into the formula, we have:
(120/240) = (6/Ns)
To isolate Ns, we can cross multiply:
120 * Ns = 6 * 240
Dividing both sides of the equation by 120, we get:
Ns = (6 * 240) / 120
Simplifying further, we have:
Ns = 12 * 2
Therefore, the secondary coil should have 24 windings.