A 4.9 kg bucket of water is raised from a well
by a rope.
The acceleration of gravity is 9.81 m/s2 .
If the upward acceleration of the bucket is
3.3 m/s2, find the force exerted by the rope
on the bucket of water.
Answer in units of N.
A 5000 kg helicopter accelerates upward at
2.25 m/s2.
The acceleration of gravity is 9.8 m/s2 .
What lift force is exerted by the air on the
propellers?
Answer in units of N.
490000
To find the force exerted by the rope on the bucket of water, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a):
F = m * a
In this case, the mass of the bucket of water is given as 4.9 kg and the upward acceleration is given as 3.3 m/s^2.
Substituting these values into the equation, we have:
F = 4.9 kg * 3.3 m/s^2
Now, we can simply multiply the mass and acceleration to find the force exerted by the rope.
F = 16.17 N (rounded to two decimal places)
Therefore, the force exerted by the rope on the bucket of water is approximately 16.17 N.