Two cars have a head-on collision.Both were traveling at 37 m/s toward each other.Car A has a mass of 432 KG.Car B has a mass of 90 KG. After impact,car A is moving backward at 3 m/s. What car B's velocity after impact?
To find Car B's velocity after the impact, we can use the law of conservation of momentum. According to this law, the total momentum before the collision is equal to the total momentum after the collision.
The total momentum before the collision can be calculated by summing the individual momenta of each car:
Momentum of Car A before collision = mass of Car A * velocity of Car A = 432 kg * 37 m/s
Momentum of Car B before collision = mass of Car B * velocity of Car B = 90 kg * ? m/s
Since Car A is moving backward after the impact, we can assign a negative sign to its velocity. Therefore, the total momentum before the collision is:
Total momentum before collision = (mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B)
Total momentum before collision = (432 kg * -3 m/s) + (90 kg * ? m/s)
Now, we can use the law of conservation of momentum to find the velocity of Car B after the impact. According to the law,
Total momentum before collision = Total momentum after collision
Since only Car A is moving after the impact, the momentum of Car B becomes zero. Hence,
(432 kg * -3 m/s) + (90 kg * ? m/s) = 0
To solve for the velocity of Car B, we rearrange the equation:
(432 kg * -3 m/s) = - (90 kg * ? m/s)
? m/s = (432 kg * -3 m/s) / -90 kg
Simplifying the equation:
? m/s = - 14.4 m/s
Hence, Car B's velocity after the impact is approximately 14.4 m/s in the opposite direction from its initial motion.