When 10.g of NaCl is reacted completely with 65g of Pb(NO3)2 according to the following reaction?
How much (grams) of PbCl2 can be produced?
2 NaCl + Pb(NO3)2 ----> PbCl2 + 2 NaNO3
52.59g of PbCl
Outline A Suitable Laboratory Procedure For Purifying A Sample Of Nacl With Contaminated With Pbcl2
To find out how much PbCl2 can be produced, we need to first determine the limiting reactant, which is the reactant that is completely consumed and therefore determines the maximum amount of product that can be formed.
To do this, we need to calculate the number of moles for each reactant.
Given:
Mass of NaCl = 10g
Mass of Pb(NO3)2 = 65g
Step 1: Calculate the number of moles of NaCl.
To calculate the number of moles, we can use the formula:
moles = mass / molar mass
The molar mass of NaCl is 22.99g/mol (sodium) + 35.45g/mol (chlorine) = 58.44g/mol.
Therefore, the number of moles of NaCl is:
moles of NaCl = 10g / 58.44g/mol
Step 2: Calculate the number of moles of Pb(NO3)2.
The molar mass of Pb(NO3)2 is 207.2g/mol (lead) + 3 * (14.01g/mol + 16.00g/mol * 3) = 331.2g/mol.
Therefore, the number of moles of Pb(NO3)2 is:
moles of Pb(NO3)2 = 65g / 331.2g/mol
Step 3: Calculate the mole ratio between NaCl and PbCl2.
From the balanced equation, we can see that the mole ratio between NaCl and PbCl2 is 2:1. This means that for every 2 moles of NaCl, 1 mole of PbCl2 is produced.
Step 4: Determine the limiting reactant.
To determine the limiting reactant, we compare the mole ratios for NaCl and Pb(NO3)2. The reactant with the smaller mole ratio will be the limiting reactant.
For NaCl, the mole ratio is 2:1.
For Pb(NO3)2, the mole ratio is 1:1.
Comparing the two mole ratios, we can see that the mole ratio for Pb(NO3)2 is smaller. Therefore, Pb(NO3)2 is the limiting reactant.
Step 5: Calculate the amount of PbCl2 produced.
Since the mole ratio between Pb(NO3)2 and PbCl2 is 1:1, the amount of PbCl2 produced will be equal to the amount of Pb(NO3)2.
Therefore, the amount of PbCl2 produced is:
mass of PbCl2 = moles of Pb(NO3)2 * molar mass of PbCl2
Using the moles of Pb(NO3)2 calculated in Step 2, we can calculate the mass of PbCl2.
I hope this explanation helps you understand how to calculate the amount of PbCl2 produced in the reaction! If you follow these steps, you should be able to find the answer to the question.