Fingernail-polish remover is primarily acetone (C3H6O). How many acetone molecules are in a bottle of acetone with a volume of 315 mL?

Question

Fingernail-polish remover is primarily acetone (C3H6O). How many acetone molecules are in a bottle of acetone with a volume of 315 mL?

(density of acetone = 0.788 g/cm3.)

I know how to get grams to the molecules once i get ml to grams. but im not sure how i use the density of acetone to convert the ml to grams

I tried setting up a conversion factor:

315ml x .788g/cm^3

but nothing crosses out

thanks

Answer 1

To convert milliliters (ml) to grams (g) using the density of a substance, you need to multiply the volume (in ml) by the density (in g/cm^3). However, in order to cancel the units properly, the density should be inverted so that the units cancel out correctly.

The density of acetone is given as 0.788 g/cm^3. To convert 315 ml to grams, you can use the following conversion factor:

315 ml * (0.788 g / 1 cm^3)

Now let's cancel the units:

315 ml * (0.788 g / 1 cm^3) * (1 cm^3 / 1 ml)

The cm^3 unit will cancel out, leaving us with grams:

315 ml * 0.788 g / 1 ml = 247.62 g

Therefore, a bottle of acetone with a volume of 315 ml is equivalent to 247.62 grams.

Now, since you mentioned that you know how to convert grams to molecules, you can proceed with your calculations using the molar mass of acetone (C3H6O).

Answer 2

To convert milliliters (ml) to grams (g), you can use the density of acetone. First, you need to convert the volume from milliliters to cubic centimeters (cm^3) because the density is given in grams per cubic centimeter (g/cm^3). The conversion factor is 1 ml = 1 cm^3.

So, to convert 315 ml to cm^3, multiply by the conversion factor:

315 ml x 1 cm^3/ml = 315 cm^3

Now, you can use the density of acetone to convert cm^3 to grams. The density of acetone is 0.788 g/cm^3. Multiply the volume in cm^3 (315 cm^3) by the density conversion factor:

315 cm^3 x 0.788 g/cm^3 = 248.22 g

Therefore, a bottle of acetone with a volume of 315 ml has a mass of approximately 248.22 grams.

Once you have the mass of acetone in grams, you can calculate the number of acetone molecules using Avogadro's number (6.022 x 10^23 molecules/mol) and the molar mass of acetone (58.08 g/mol).

Answer 3

You can use the Density equation: Density=Mass/volume. They give you the volume and density so you need to manipulate the Density equation to solve for mass. That should give you the grams of acetone in the bottle of acetone and you can use that to solve for the acetone molecules.