During the past month, you withdrew $22 from your savings account and then deposited $24. If your balance at the end of the month is $120, how much did you have in your account at the beginning of the month?
22 24
-- = --
120 x
2880
----
22x
x=130.9
Is this correct?
No, this is not a multiplication or division statement.
Simply look at it this way, your balance increased by $2. and it is now $120
So it must have been $118
I you feel you must set this up as an equation, you could say
x - 22 + 24 = 120 and solve this to get
x = 118
To solve this problem, we can set up an equation. Let's denote the amount you had in your account at the beginning of the month as "x".
First, you withdrew $22 from your account, so your balance decreased by $22. Therefore, your balance after the withdrawal is x - 22.
Next, you deposited $24 into your account, so your balance increased by $24. Therefore, your balance after the deposit is (x - 22) + 24, which simplifies to (x + 2).
According to the information given, your balance at the end of the month is $120. So we have the equation:
(x + 2) = 120
Now, to solve for x, we can isolate it on one side of the equation:
x + 2 = 120
x = 120 - 2
x = 118
Therefore, you had $118 in your account at the beginning of the month.
Regarding your calculation:
22/120 = 24/x
To solve this equation, you cross-multiplied and got the result:
22x = (24 * 120)
However, there seems to be an error in your calculation. The correct calculation would be:
22x = 24 * 120
22x = 2880
Dividing both sides of the equation by 22:
x = 2880 / 22
x ≈ 130.9
Therefore, your calculation is not correct. The correct answer is x = 118, as explained earlier.