CALCULUS BC
 👍
 👎
 👁

 👍
 👎
Respond to this Question
Similar Questions

calculus
A Particle moves along the xaxis so that at any time t>0, its acceleration is given by a(t)= ln(1+2^t). If the velocity of the particle is 2 at time t=1, then the velocity of the particle at time t=2 is? The correct answer is

Calculus
A particle, initially at rest, moves along the xaxis such that its acceleration at time t>0 is given by a(t)=cos(t). At the time t=0, its position is x=3. How do I find the position function for the particle? I tried integrating

Physics
I need help with this question with explanation. Thanks A particle of mass m starts from rest at position x = 0 and time t = 0. It moves along the positive xaxis under the influence of a single force Fx = bt, where b is a

HS Calculus
Having trouble with this questions. Please help. A particle moves on the xaxis so that its position at any time t (is greater than or equal to) 0 is given by x(t) = 2te^t a) Find the acceleration of the particle at t=0 b)find

Calculus
A particle moves along the xaxis so that at time "t" its position is given by s(t)=(t+3)(t1)^3 ,t>0 For what values of "t" is the velocity of the particle increasing? a) 00 d) the velocity is never increasing

AP Calculus
A particle moving along xaxis has velocity v(t) = sin(4t) at time t. If the particle is at x=4 when t=0, determine the position of the particle when t=pi/2.

Calc
A particle moves along the xaxis in such a way that it's position in time t for t is greator or equal to 0 is given by x= 1/3t^3  3t^2 +8 A) show that at time t= 0 the particle is moving to the right. B) find all values of t for

Calculus
A particle moves along the xaxis with the velocity given by v(t)=3t/(1+t^2) for t >or equal to 0. When t=0, the particle is at the point (4,0). 1. Determine the maximum velocity for the particle. Justify your answer. 2. Determine

calculus
a particle moves along the y axis so that its position at any time t, for 0 is less than or equal to t which is less than or equal to 5, is given by y(t)=t^418t^2. in which intervals is the particle speeding up?

calculus
a particle moves along the xaxis in such a way that its acceleration at any time t is given by a(t)= 6t  18. At time t = 0, the velocity v(t) = 24. and at time t = 1, the position x(t) = 20 i have to find the expression for the

Calculus
a particle starts at time t = 0 and moves along the x axis so that its position at any time t>= 0 is given by x(t) = ((t1)^3)(2t3) a.find the velocity of the particle at any time t>= 0 b. for what values of t is the velocity of

calculus
5. A particle moves along the y – axis with velocity given by v(t)=tsine(t^2) for t>=0 . a. In which direction (up or down) is the particle moving at time t = 1.5? Why? b. Find the acceleration of the particle at time t= 1.5. Is
You can view more similar questions or ask a new question.