(b^(-4y+7))(b^y) / b

I got 1 / b^(3y-8)

but the answer is supposed to be 1 / b^(3y+6) ?

could someone write the steps to solving this?

I just solved it and i know how to get 1 / b^(3y+6) as the answer

but, if for the exponent -4y+7 if it isn't -(4y+7) I wouldn't move it to the bottom of a fraction?

by answer I meant b^-3y+6

You may put the exponents in the numerator or denominator.

a3= 1/a-3

sometimes teachers have beginning students move them around just for practice.

To simplify the expression (b^(-4y+7))(b^y) / b, we can use the properties of exponents. Here are the steps to solve it:

Step 1: Simplify the numerator by using the exponent rule for multiplication. When you multiply two exponents with the same base, you add their exponents. In this case, we have (b^(-4y+7))(b^y), which can be simplified as b^((-4y+7)+y).

Step 2: Simplify the exponent in the numerator. (-4y+7)+y can be simplified to -3y+7.

Step 3: Divide the numerator by the denominator. b^(-3y+7) / b can be simplified by subtracting the exponents. When dividing two exponents with the same base, you subtract the exponent in the denominator from the exponent in the numerator. In this case, -3y+7 - 1 = -3y+6.

Therefore, the simplified form of (b^(-4y+7))(b^y) / b is 1 / b^(3y+6).