If the amount of raidoactive iodine-123 in a sample decreases from 0.4 to 0.1 g in 26.2 hours, what is the half-life of iodine-123?
ln(No/N) = kt
No = 0.4
N = 0.1
t = 26.2 hours.
Solve for k. Then
k = 0.693/t1/2
Solve for t1/2>/sub>
No = 0.4
N = 0.1
t = 26.2 hours.
Solve for k. Then
k = 0.693/t1/2
Solve for t1/2>/sub>