Two cars have a head on collision. Both are traveling at 28 m/s toward each othe. Car A has a mass of 700 kg and car B has a mass of 904kg. What is car B velocity after the impact?
use conservation of momentum.
Ma*Va+Mb*Vb=Ma*Va' + Mb*Vb'
28(Ma-Mb)=
well, at this point, you have two unknowns, and you have to stop. You cannot use conservation of energy, you have no basis to assume it was an elastic collision.
To find the velocity of car B after the impact, we need to apply the principles of conservation of momentum.
The law of conservation of momentum states that in a collision, the total momentum before the collision is equal to the total momentum after the collision.
The momentum of an object is calculated by multiplying its mass and velocity. So, the momentum can be written as:
Momentum = mass × velocity
Let's calculate the initial momentum before the collision for both cars:
Momentum of Car A = mass of Car A × velocity of Car A
= 700 kg × 28 m/s
Momentum of Car B = mass of Car B × velocity of Car B
= 904 kg × (negative 28 m/s) [since Car B is moving in the opposite direction]
Since the cars collide and come to a stop, the total momentum after the collision will be zero.
Therefore, we can write the equation as:
Momentum of Car A + Momentum of Car B = 0
(700 kg × 28 m/s) + (904 kg × (negative 28 m/s)) = 0
Simplifying the equation:
19600 kg·m/s - 25312 kg·m/s = 0
Now, let's add the momenta:
-5712 kg·m/s = 0
To find the velocity of car B after the impact, we can rearrange the equation:
Velocity of Car B = (-Momentum of Car A) / mass of Car B
Substituting the given values:
Velocity of Car B = (-5712 kg·m/s) / 904 kg
= -6.32 m/s
Therefore, the velocity of car B after the impact is approximately -6.32 m/s.