A basketball player makes a jump shot. The 0.700 kg ball is released at a height of 1.90 m above the floor with a speed of 7.00 m/s. The ball goes through the net 3.10 m above the floor at a speed of 3.70 m/s. What is the work done on the ball by air resistance, a nonconservative force?
didn't I answer it? Let me see your work.
yes it was, but it was wrong. I did )Inital KE + inital PE)- W = (Final KE + final PE) and got 8.2425
To calculate the work done on the ball by air resistance, we need to use the work-energy principle. According to the principle, the work done on an object is equal to the change in its kinetic energy.
First, we need to find the initial kinetic energy of the ball. This can be calculated using the formula:
KE_initial = (1/2) * mass * velocity^2
Substituting the values we have:
KE_initial = (1/2) * 0.700 kg * (7.00 m/s)^2
Now, we need to find the final kinetic energy of the ball. This can be calculated using the same formula:
KE_final = (1/2) * mass * velocity^2
Substituting the values we have:
KE_final = (1/2) * 0.700 kg * (3.70 m/s)^2
Next, we can find the difference in kinetic energy:
ΔKE = KE_final - KE_initial
Finally, the work done by air resistance can be calculated as the negative of the change in kinetic energy:
Work by air resistance = -ΔKE
By performing these calculations, you can find the work done by air resistance on the basketball player's shot.