Two parallel chords lie on opposite sides of the centre of a circle of radius 13cm.their lengths are 10cm and 24cm.what is the distance between the chords?

Been there

in the diagram below of circle o, diameter

AB IS PARALLEL TO CHORD cd.
if CD=70, WHAT IS MAC?

I do not know.

5cm

To find the distance between the parallel chords, we can use the formula for the distance between two parallel lines in a plane.

Let's call the chords AB and CD, where AB is the chord with length 10cm and CD is the chord with length 24cm.

First, we need to find the perpendicular distance between the center of the circle and the line AB. Since the line AB is a chord, the perpendicular distance between the center and AB is the radius of the circle.

Given that the radius of the circle is 13cm, the perpendicular distance between the center and AB is also 13cm.

Next, we need to find the perpendicular distance between the center of the circle and the line CD. Similarly, the perpendicular distance between the center and CD is 13cm.

Therefore, the distance between the two parallel chords AB and CD is equal to the difference between the perpendicular distances of the two chords from the center of the circle.

Distance = |(Perpendicular distance of AB) - (Perpendicular distance of CD)|
= |13cm - 13cm|
= 0cm

So, the distance between the chords AB and CD is 0cm.