Solve the system of equations by the substitution method

X+9y=32
2x+4y=8

x = (32 - 9y)

so
2(32 - 9y) + 4 y = 8

64 -18 y + 4 y = 8

56 = 14 y

y = 4
go back and get x now

i need help solving this 3x y=4D

To solve the system of equations using the substitution method, we will solve one equation for one variable and substitute that expression into the other equation.

Let's solve the first equation for x:
x = 32 - 9y

Now, substitute the value of x into the second equation:
2(32 - 9y) + 4y = 8

Distribute and simplify:
64 - 18y + 4y = 8

Combine like terms:
-14y + 64 = 8

Move 64 to the other side by subtracting it from both sides:
-14y = 8 - 64
-14y = -56

Divide both sides by -14 to solve for y:
y = -56 / -14
y = 4

Now that we have the value of y, substitute it back into the first equation to solve for x:
x + 9(4) = 32

Simplify and solve for x:
x + 36 = 32
x = 32 - 36
x = -4

The solution to the system of equations is x = -4 and y = 4.

To solve the system of equations using the substitution method, we will solve one equation for one variable and substitute it into the other equation.

Let's solve the first equation for x in terms of y:
x = 32 - 9y

Now, substitute this expression for x in the second equation:
2(32 - 9y) + 4y = 8

Distribute the 2:
64 - 18y + 4y = 8

Combine like terms:
-14y + 64 = 8

Subtract 64 from both sides:
-14y = -56

Divide both sides by -14:
y = 4

Now that we have the value of y, we can substitute it back into the first equation to find the value of x:
x + 9(4) = 32

x + 36 = 32

Subtract 36 from both sides:
x = -4

Therefore, the solution to the system of equations is x = -4 and y = 4.